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Last updated on September 27, 2025
We use the derivative of 2x³, which is 6x², to measure how a cubic function changes as x changes slightly. Derivatives are useful for calculating various quantities like velocity and acceleration in physics. We will now explore the derivative of 2x³ in detail.
We now understand the derivative of 2x³. It is commonly represented as d/dx (2x³) or (2x³)', and its value is 6x². The function 2x³ has a well-defined derivative, which means it is differentiable across its entire domain.
The key concepts are mentioned below:
Polynomial Function: A function like 2x³ is a polynomial of degree 3.
Power Rule: The rule for differentiating terms like 2x³.
Coefficient: The number 2 in 2x³ is a constant multiplier.
The derivative of 2x³ can be denoted as d/dx (2x³) or (2x³)'. The formula we use to differentiate 2x³ is: d/dx (2x³) = 6x² (or) (2x³)' = 6x²
This formula applies to all x.
We can derive the derivative of 2x³ using several proofs. To show this, we will use basic differentiation rules.
There are various methods to prove this, such as:
We will now demonstrate that the differentiation of 2x³ results in 6x² using the mentioned methods:
The derivative of 2x³ can be found using the First Principle, which expresses the derivative as the limit of the difference quotient. To find the derivative of 2x³ using the first principle, consider f(x) = 2x³. Its derivative can be expressed as the following limit. f'(x) = limₕ→₀ [f(x + h) - f(x)] / h … (1) Given that f(x) = 2x³, we write f(x + h) = 2(x + h)³. Substituting these into equation (1), f'(x) = limₕ→₀ [2(x + h)³ - 2x³] / h = limₕ→₀ [2(x³ + 3x²h + 3xh² + h³) - 2x³] / h = limₕ→₀ [6x²h + 6xh² + 2h³] / h = limₕ→₀ [6x² + 6xh + 2h²] = 6x² (as h approaches 0) Hence, proved.
The power rule states that d/dx (xⁿ) = nxⁿ⁻¹. For 2x³, we have: d/dx (2x³) = 2 * d/dx (x³) Using the power rule: d/dx (x³) = 3x². Thus, d/dx (2x³) = 2 * 3x² = 6x².
When a function is differentiated multiple times, the resulting derivatives are referred to as higher-order derivatives. Higher-order derivatives can be complex. To understand them better, consider a car where speed changes (first derivative) and the acceleration changes (second derivative). Higher-order derivatives make it easier to understand functions like 2x³.
The first derivative of a function is written as f′(x), indicating how the function changes or its slope at a certain point. The second derivative is derived from the first derivative, denoted as f′′(x). Similarly, the third derivative, f′′′(x), results from the second derivative, and this pattern continues.
For the nth Derivative of 2x³, we generally use fⁿ(x) for the nth derivative of a function f(x), which tells us the change in the rate of change.
When x is 0, the derivative of 2x³ = 6(0)² = 0.
Students frequently make mistakes when differentiating 2x³. These mistakes can be resolved by understanding the proper solutions. Here are a few common mistakes and ways to solve them:
Calculate the derivative of (2x³ · x²)
Here, we have f(x) = 2x³ · x². Using the product rule, f'(x) = u′v + uv′ In the given equation, u = 2x³ and v = x². Let’s differentiate each term, u′= d/dx (2x³) = 6x² v′= d/dx (x²) = 2x Substituting into the given equation, f'(x) = (6x²) · (x²) + (2x³) · (2x) Let’s simplify terms to get the final answer, f'(x) = 6x⁴ + 4x⁴ = 10x⁴ Thus, the derivative of the specified function is 10x⁴.
We find the derivative of the given function by dividing the function into two parts.
The first step is finding its derivative and then combining them using the product rule to get the final result.
A new technology company models its growth with the function y = 2x³, where y represents the number of users and x represents time in years. If x = 2 years, determine the rate of user growth.
We have y = 2x³ (model of user growth)...(1) Now, we will differentiate equation (1) Take the derivative of 2x³: dy/dx = 6x² Given x = 2 (substitute this into the derivative) dy/dx = 6(2)² = 6 · 4 = 24 Hence, the rate of user growth at x = 2 years is 24 users per year.
We find the rate of user growth at x = 2 years as 24 users per year, which means that at this point in time, the user count is increasing at a rate of 24 users annually.
Derive the second derivative of the function y = 2x³.
The first step is to find the first derivative, dy/dx = 6x²...(1) Now we will differentiate equation (1) to get the second derivative: d²y/dx² = d/dx [6x²] d²y/dx² = 12x Therefore, the second derivative of the function y = 2x³ is 12x.
We use the step-by-step process, where we start with the first derivative.
Then, we differentiate 6x² to find the second derivative, resulting in 12x.
Prove: d/dx (2x³) = 6x².
Let's use the power rule: Consider f(x) = 2x³ Using the power rule, we differentiate: d/dx (2x³) = 2 * d/dx (x³) = 2 * 3x² = 6x² Hence proved.
In this step-by-step process, we used the power rule to differentiate the equation.
We multiplied the derivative by the coefficient 2, resulting in 6x².
Solve: d/dx (2x³/x)
To differentiate the function, we simplify first: 2x³/x = 2x² Now differentiate: d/dx (2x²) = 4x Therefore, d/dx (2x³/x) = 4x.
In this process, we first simplified the given function and then applied the power rule to differentiate it, obtaining the final result.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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